Decode XORed Array - Array - Easy - LeetCode
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Decode XORed Array - Array - Easy - LeetCode

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  • 1The encoded array is derived from the original array using XOR operations between consecutive elements.
  • 2Given the first element of the original array, the entire array can be reconstructed uniquely.
  • 3The solution has a time complexity of O(n) and a space complexity of O(n).

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"The encoded array is derived from the original array using XOR operations between consecutive elements."

Decode XORed Array - Array - Easy - LeetCode

There is a hidden integer array arr that consists of n non-negative integers.

It was encoded into another integer array encoded of length n - 1, such that encoded[i] = arr[i] XOR arr[i + 1]. For example, if arr = [1,0,2,1], then encoded = [1,2,3].

You are given the encoded array. You are also given an integer first, that is the first element of arr, i.e. arr[0].

Return the original array arr. It can be proved that the answer exists and is unique.

Example 1:

Input: encoded = [1,2,3], first = 1 Output: [1,0,2,1] Explanation: If arr = [1,0,2,1], then first = 1 and encoded = [1 XOR 0, 0 XOR 2, 2 XOR 1] = [1,2,3] Example 2:

Input: encoded = [6,2,7,3], first = 4 Output: [4,2,0,7,4]

Constraints:

2 <= n <= 104 encoded.length == n - 1 0 <= encoded[i] <= 105 0 <= first <= 105

public class Solution {
 public int[] Decode(int[] encoded, int first) {
 var arr = new int[encoded.Length+1];
 arr[0]=first;
 for(int i=1;i<encoded.Length+1;i++){
 arr[i]=arr[i-1] ^ encoded[i-1];
 }
 
 return arr;
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

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sumitc91

Published on 10 January 2021 · 1 min read · 182 words

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