Reformat Phone Number - String - Easy - LeetCode
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Reformat Phone Number - String - Easy - LeetCode

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  • 1To reformat a phone number, remove spaces and dashes before grouping digits into blocks of 3 or 2.
  • 2If more than 4 digits remain, create blocks of 3 until 4 or fewer digits are left for final formatting.
  • 3The final grouping rules specify that 4 digits split into two blocks of 2, while 3 digits form a single block of 3.

AI-generated summary · May not capture all nuances

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"To reformat a phone number, remove spaces and dashes before grouping digits into blocks of 3 or 2."

Reformat Phone Number - String - Easy - LeetCode

You are given a phone number as a string number. number consists of digits, spaces ' ', and/or dashes '-'.

You would like to reformat the phone number in a certain manner. Firstly, remove all spaces and dashes. Then, group the digits from left to right into blocks of length 3 until there are 4 or fewer digits. The final digits are then grouped as follows:

2 digits: A single block of length 2. 3 digits: A single block of length 3. 4 digits: Two blocks of length 2 each. The blocks are then joined by dashes. Notice that the reformatting process should never produce any blocks of length 1 and produce at most two blocks of length 2.

Return the phone number after formatting.

Example 1:

Input: number = "1-23-45 6" Output: "123-456" Explanation: The digits are "123456". Step 1: There are more than 4 digits, so group the next 3 digits. The 1st block is "123". Step 2: There are 3 digits remaining, so put them in a single block of length 3. The 2nd block is "456". Joining the blocks gives "123-456". Example 2:

Input: number = "123 4-567" Output: "123-45-67" Explanation: The digits are "1234567". Step 1: There are more than 4 digits, so group the next 3 digits. The 1st block is "123". Step 2: There are 4 digits left, so split them into two blocks of length 2. The blocks are "45" and "67". Joining the blocks gives "123-45-67". Example 3:

Input: number = "123 4-5678" Output: "123-456-78" Explanation: The digits are "12345678". Step 1: The 1st block is "123". Step 2: The 2nd block is "456". Step 3: There are 2 digits left, so put them in a single block of length 2. The 3rd block is "78". Joining the blocks gives "123-456-78". Example 4:

Input: number = "12" Output: "12" Example 5:

Input: number = "--17-5 229 35-39475 " Output: "175-229-353-94-75"

Constraints:

2 <= number.length <= 100 number consists of digits and the characters '-' and ' '. There are at least two digits in number.

public class Solution {
 public string ReformatNumber(string number) {
 number = number.Replace("-", ""); 
 number = number.Replace(" ", ""); 
 StringBuilder sb = new StringBuilder();
 int index = 0;
 int count = number.Length;
 while (count > 4) { // as long as there are more than 4 left characters, we add 3 of them and a '-' for each time.
 for (int i=0; i<3; i++) {
 sb.Append(number[index++]);
 count--;
 }
 sb.Append('-');
 }
 if (count < 4) { // less than 4 characters, add them directly.
 for (int i=0; i<count; i++) {
 sb.Append(number[index++]);
 }
 } else { // When there are exact 4 characters left, we split them by groups of size 2.
 for (int i=0; i<2; i++) {
 sb.Append(number[index++]);
 }
 sb.Append('-');
 for (int i=0; i<2; i++) {
 sb.Append(number[index++]);
 }
 }
 return sb.ToString();
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

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sumitc91

Published on 5 January 2021 · 2 min read · 481 words

Part of AskGif Blog · coding

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Reformat Phone Number - String - Easy - LeetCode | AskGif Blog