Sort Array by Increasing Frequency - Array - Medium - LeetCode
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Sort Array by Increasing Frequency - Array - Medium - LeetCode

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  • 1The array is sorted by the frequency of values in increasing order.
  • 2Values with the same frequency are sorted in decreasing order.
  • 3The solution has a time complexity of O(nlogn) and space complexity of O(n).

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"The array is sorted by the frequency of values in increasing order."

Sort Array by Increasing Frequency - Array - Medium - LeetCode

Given an array of integers nums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order.

Return the sorted array.

Example 1:

Input: nums = [1,1,2,2,2,3] Output: [3,1,1,2,2,2] Explanation: '3' has a frequency of 1, '1' has a frequency of 2, and '2' has a frequency of 3. Example 2:

Input: nums = [2,3,1,3,2] Output: [1,3,3,2,2] Explanation: '2' and '3' both have a frequency of 2, so they are sorted in decreasing order. Example 3:

Input: nums = [-1,1,-6,4,5,-6,1,4,1] Output: [5,-1,4,4,-6,-6,1,1,1]

Constraints:

1 <= nums.length <= 100 -100 <= nums[i] <= 100

public class Solution {
 public int[] FrequencySort(int[] nums) {
 var map = new Dictionary<int,int>();
 var res = new int[nums.Length];
 for(int i=0;i<nums.Length;i++){ 
 if(map.ContainsKey(nums[i])){
 map[nums[i]]++; 
 }
 else{
 map.Add(nums[i],1);
 }
 }
 
 map = map.OrderBy(x=>x.Value).ThenByDescending(x=>x.Key).ToDictionary(x=> x.Key, x=>x.Value);
 int index=0;
 foreach(var item in map){ 
 for(int i=0;i<item.Value;i++){
 res[index]=item.Key;
 index++;
 }
 }
 
 return res;
 }
}

Time Complexity: O(nlogn)

Space Complexity: O(n)

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sumitc91

Published on 3 November 2020 · 1 min read · 162 words

Part of AskGif Blog · coding

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