Jump Game - Array - Medium - LeetCode
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Jump Game - Array - Medium - LeetCode

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  • 1The Jump Game problem involves determining if you can reach the last index of an array based on jump lengths.
  • 2Example inputs demonstrate that certain configurations allow reaching the end, while others do not due to zero jump lengths.
  • 3The provided solution uses dynamic programming with a time complexity of O(n^2) and space complexity of O(n).

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"The Jump Game problem involves determining if you can reach the last index of an array based on jump lengths."

Jump Game - Array - Medium - LeetCode

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

Example 1:

Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index. Example 2:

Input: nums = [3,2,1,0,4] Output: false Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index.

Constraints:

1 <= nums.length <= 3 * 10^4 0 <= nums[i][j] <= 10^5

public class Solution {
 public bool CanJump(int[] nums) {
 var T = new int[nums.Length];
 for(int i=0;i<nums.Length;i++){
 T[i]=int.MaxValue;
 }
 T[0]=0;
 
 for(int i=0;i<T.Length;i++){
 if(T[i]==int.MaxValue){
 break;
 }
 for(int j=i+1;j<=nums[i]+i && j < T.Length;j++){ 
 T[j]=Math.Min(T[j],T[i]+1);
 }
 }
 
 return T[nums.Length-1]!=int.MaxValue;
 }
}

Time Complexity: O(n^2)

Space Complexity: O(n)

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sumitc91

Published on 28 October 2020 · 1 min read · 154 words

Part of AskGif Blog · coding

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