Rotate Image - Array - Medium - LeetCode
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Rotate Image - Array - Medium - LeetCode

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  • 1The task is to rotate an n x n 2D matrix by 90 degrees clockwise in-place.
  • 2The solution requires swapping elements without allocating a new matrix, ensuring O(1) space complexity.
  • 3Examples demonstrate the rotation of various matrix sizes, from 1x1 to 4x4.

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AskGif

"The task is to rotate an n x n 2D matrix by 90 degrees clockwise in-place."

Rotate Image - Array - Medium - LeetCode

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [[7,4,1],[8,5,2],[9,6,3]] Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]] Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]] Example 3:

Input: matrix = [[1]] Output: [[1]] Example 4:

Input: matrix = [[1,2],[3,4]] Output: [[3,1],[4,2]]

Constraints:

matrix.length == n matrix[i].length == n 1 <= n <= 20 -1000 <= matrix[i][j] <= 1000

public class Solution {
 public void Rotate(int[][] matrix) {
 if(matrix.Length==0){
 return;
 }
 
 int s = 0;
 int e = matrix.Length-1;
 while(s < e){
 var temp = matrix[s];
 matrix[s]=matrix[e];
 matrix[e]=temp;
 s++;
 e--;
 }
 
 for(int i=0; i< matrix.Length;i++){
 for(int j=i+1;j<matrix.Length;j++){
 int temp = matrix[i][j];
 matrix[i][j]=matrix[j][i];
 matrix[j][i]=temp;
 }
 }
 }
}

Time Complexity: O(m*n)

Space Complexity: O(1)

Where m and n are rows and columns of matrix.

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sumitc91

Published on 26 October 2020 · 1 min read · 160 words

Part of AskGif Blog · coding

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