Number of Recent Calls - Queue - Easy - LeetCode
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Number of Recent Calls - Queue - Easy - LeetCode

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  • 1The RecentCounter class tracks the number of requests within the last 3000 milliseconds using a queue data structure.
  • 2The ping method adds a new request and returns the count of requests in the inclusive range [t - 3000, t].
  • 3Each call to ping is guaranteed to have a strictly larger value of t than the previous call, ensuring ordered processing.

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Key Insight
AskGif

"The RecentCounter class tracks the number of requests within the last 3000 milliseconds using a queue data structure."

Number of Recent Calls - Queue - Easy - LeetCode

You have a RecentCounter class which counts the number of recent requests within a certain time frame.

Implement the RecentCounter class:

RecentCounter() Initializes the counter with zero recent requests. int ping(int t) Adds a new request at time t, where t represents some time in milliseconds and returns the number of requests that have happened in the past 3000 milliseconds (including the new request). Specifically, return the number of requests that have happened in the inclusive range [t - 3000, t]. It is guaranteed that every call to ping uses a strictly larger value of t than the previous call.

Example 1:

Input ["RecentCounter", "ping", "ping", "ping", "ping"] [[], [1], [100], [3001], [3002]] Output [null, 1, 2, 3, 3]

Explanation RecentCounter recentCounter = new RecentCounter(); recentCounter.ping(1); // requests = [1], range is [-2999,1], return 1 recentCounter.ping(100); // requests = [1, 100], range is [-2900,100], return 2 recentCounter.ping(3001); // requests = [1, 100, 3001], range is [1,3001], return 3 recentCounter.ping(3002); // requests = [1, 100, 3001, 3002], range is [2,3002], return 3

Constraints:

1 <= t <= 109 Each test case will call ping with strictly increasing values of t. At most 104 calls will be made to ping.

public class RecentCounter {
 Queue<int> queue;
 public RecentCounter() {
 queue = new Queue<int>();
 }
 
 public int Ping(int t) {
 if(queue.Count()==0){
 queue.Enqueue(t); 
 }
 else{
 queue.Enqueue(t);
 while(true){
 int diff = t - queue.Peek();
 if(diff>3000){
 queue.Dequeue();
 }
 else{
 break;
 }
 } 
 }
 
 return queue.Count();
 }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * RecentCounter obj = new RecentCounter();
 * int param_1 = obj.Ping(t);
 */

Time Complexity: O(n)

Space Complexity: O(n)

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sumitc91

Published on 16 October 2020 · 1 min read · 271 words

Part of AskGif Blog · coding

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Number of Recent Calls - Queue - Easy - LeetCode | AskGif Blog