Same Tree - Tree - Easy - LeetCode
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Same Tree - Tree - Easy - LeetCode

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  • 1The function checks if two binary trees are structurally identical and have the same node values.
  • 2Example inputs demonstrate that trees with different structures or values return false.
  • 3The algorithm has a time complexity of O(n) and a space complexity of O(1).

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Key Insight
AskGif

"The function checks if two binary trees are structurally identical and have the same node values."

Same Tree - Tree - Easy - LeetCode

Given two binary trees, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical and the nodes have the same value.

Example 1:

Input: 1 1 / \ / \ 2 3 2 3

[1,2,3], [1,2,3]

Output: true Example 2:

Input: 1 1 / \ 2 2

[1,2], [1,null,2]

Output: false Example 3:

Input: 1 1 / \ / \ 2 1 1 2

[1,2,1], [1,1,2]

Output: false

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 * public int val;
 * public TreeNode left;
 * public TreeNode right;
 * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {
 * this.val = val;
 * this.left = left;
 * this.right = right;
 * }
 * }
 */
public class Solution {
 public bool IsSameTree(TreeNode p, TreeNode q) {
 if(p==null & q==null){
 return true;
 }
 if(p==null||q==null){
 return false;
 }
 if(p.val!=q.val){
 return false;
 }
 
 return IsSameTree(p.left,q.left) && IsSameTree(p.right,q.right);
 }
}

Time Complexity: O(n)

Space Complexity: O(1)

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sumitc91

Published on 6 October 2020 · 1 min read · 170 words

Part of AskGif Blog · coding

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