Shuffle String - Sort - Easy - LeetCode
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Shuffle String - Sort - Easy - LeetCode

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  • 1The problem involves shuffling a string based on a given array of indices.
  • 2Each character in the string moves to a new position specified by the indices array.
  • 3The solution has a time complexity of O(n) and a space complexity of O(n).

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AskGif

"The problem involves shuffling a string based on a given array of indices."

Shuffle String - Sort - Easy - LeetCode

Given a string s and an integer array indices of the same length.

The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string.

Return the shuffled string.

Example 1:

Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3] Output: "leetcode" Explanation: As shown, "codeleet" becomes "leetcode" after shuffling. Example 2:

Input: s = "abc", indices = [0,1,2] Output: "abc" Explanation: After shuffling, each character remains in its position. Example 3:

Input: s = "aiohn", indices = [3,1,4,2,0] Output: "nihao" Example 4:

Input: s = "aaiougrt", indices = [4,0,2,6,7,3,1,5] Output: "arigatou" Example 5:

Input: s = "art", indices = [1,0,2] Output: "rat"

Constraints:

s.length == indices.length == n 1 <= n <= 100 s contains only lower-case English letters. 0 <= indices[i] < n All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n - 1).

public class Solution {
 public string RestoreString(string s, int[] indices) {
 var arr = s.ToCharArray();
 for(int i=0;i<s.Length;i++){
 arr[indices[i]]=s[i]; 
 }
 
 return new string(arr);
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

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sumitc91

Published on 5 October 2020 · 1 min read · 182 words

Part of AskGif Blog · coding

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