Find Smallest Letter Greater Than Target - Array - Easy - LeetCode
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Find Smallest Letter Greater Than Target - Array - Easy - LeetCode

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  • 1The task is to find the smallest letter in a sorted array that is greater than a given target letter.
  • 2The solution uses a binary search approach, achieving a time complexity of O(log n).
  • 3Letters wrap around, meaning if the target is the highest letter, the answer is the first letter in the array.

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"The task is to find the smallest letter in a sorted array that is greater than a given target letter."

Find Smallest Letter Greater Than Target - Array - Easy - LeetCode

Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target.

Letters also wrap around. For example, if the target is target = 'z' and letters = ['a', 'b'], the answer is 'a'.

Examples: Input: letters = ["c", "f", "j"] target = "a" Output: "c"

Input: letters = ["c", "f", "j"] target = "c" Output: "f"

Input: letters = ["c", "f", "j"] target = "d" Output: "f"

Input: letters = ["c", "f", "j"] target = "g" Output: "j"

Input: letters = ["c", "f", "j"] target = "j" Output: "c"

Input: letters = ["c", "f", "j"] target = "k" Output: "c" Note: letters has a length in range [2, 10000]. letters consists of lowercase letters, and contains at least 2 unique letters. target is a lowercase letter.

public class Solution {
 public char NextGreatestLetter(char[] letters, char target) { 
 if(target>=letters[letters.Length-1]){
 return letters[0];
 }
 
 int low = 0;
 int high = letters.Length-1; 
 while(low<high){ 
 int mid = low + (high-low)/2; 
 if(letters[mid]<=target){
 low = mid+1;
 }
 else{
 high=mid;
 }
 
 } 
 
 return letters[high];
 }
}

Time Complexity: O(logn)

Space Complexity: O(1)

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sumitc91

Published on 3 October 2020 · 1 min read · 195 words

Part of AskGif Blog · coding

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