Given a date string in the form Day Month Year, where:
Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}. Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}. Year is in the range [1900, 2100]. Convert the date string to the format YYYY-MM-DD, where:
YYYY denotes the 4 digit year. MM denotes the 2 digit month. DD denotes the 2 digit day.
Example 1:
Input: date = "20th Oct 2052" Output: "2052-10-20" Example 2:
Input: date = "6th Jun 1933" Output: "1933-06-06" Example 3:
Input: date = "26th May 1960" Output: "1960-05-26"
Constraints:
The given dates are guaranteed to be valid, so no error handling is necessary.
public class Solution {
public string ReformatDate(string date) {
var arr = date.Split(' ');
var sb = new StringBuilder();
sb.Append(arr[2]);
sb.Append("-");
sb.Append(GetMonth(arr[1]));
sb.Append("-");
if(Char.IsDigit(arr[0][1])){
sb.Append(arr[0].Substring(0,2));
}
else{
sb.Append("0"+arr[0][0]);
}
return sb.ToString();
}
private string GetMonth(string month){
switch(month){
case "Jan":
return "01";
case "Feb":
return "02";
case "Mar":
return "03";
case "Apr":
return "04";
case "May":
return "05";
case "Jun":
return "06";
case "Jul":
return "07";
case "Aug":
return "08";
case "Sep":
return "09";
case "Oct":
return "10";
case "Nov":
return "11";
case "Dec":
return "12";
}
return "";
}
}Time Complexity: O(1)
Space Complexity: O(n)
