Count Odd Numbers in an Interval Range - Math - Easy - LeetCode

Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).

Example 1:

Input: low = 3, high = 7 Output: 3 Explanation: The odd numbers between 3 and 7 are [3,5,7]. Example 2:

Input: low = 8, high = 10 Output: 1 Explanation: The odd numbers between 8 and 10 are [9].

Constraints:

0 <= low <= high <= 10^9

public class Solution {
 public int CountOdds(int low, int high) { 
 
 if(low%2==0 && high%2==0){
 return (high-low)/2;
 }
 
 return ((high-low)/2)+1;
 }
}

Time Complexity: O(1)

Space Complexity: O(1)