Self Dividing Numbers - Math - Easy - LeetCode
💻 coding

Self Dividing Numbers - Math - Easy - LeetCode

1 min read 169 words
1 min read
ShareWhatsAppPost on X
  • 1A self-dividing number is divisible by each of its digits and cannot contain the digit zero.
  • 2The function outputs all self-dividing numbers within a specified range, including the bounds.
  • 3The algorithm has a time complexity of O(n) and a space complexity of O(1).

AI-generated summary · May not capture all nuances

Key Insight
AskGif

"A self-dividing number is divisible by each of its digits and cannot contain the digit zero."

Self Dividing Numbers - Math - Easy - LeetCode

A self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1: Input: left = 1, right = 22 Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22] Note:

The boundaries of each input argument are 1 <= left <= right <= 10000.

public class Solution {
 public IList<int> SelfDividingNumbers(int left, int right) {
 var result = new List<int>();
 for(int i=left;i<=right;i++){
 if(i<10){
 result.Add(i);
 }
 else if(IsValid(i)){
 result.Add(i);
 }
 }
 
 return result;
 }
 
 private bool IsValid(int num){
 int temp = num;
 while(temp>0){
 int mod = temp%10;
 if(mod==0 || num%mod!=0){
 return false;
 }
 temp=temp/10;
 }
 
 return true;
 }
}

Time Complexity: O(n)

Space Complexity: O(1)

Enjoyed this article?

Share it with someone who'd find it useful.

ShareWhatsAppPost on X

sumitc91

Published on 1 October 2020 · 1 min read · 169 words

Part of AskGif Blog · coding

You might also like

Self Dividing Numbers - Math - Easy - LeetCode | AskGif Blog