Toeplitz Matrix - Array - Easy - LeetCode
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Toeplitz Matrix - Array - Easy - LeetCode

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  • 1A Toeplitz matrix has the same elements on every diagonal from top-left to bottom-right.
  • 2The function returns True if the matrix is Toeplitz and False otherwise.
  • 3The solution has a time complexity of O(m*n) and a space complexity of O(1).

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Key Insight
AskGif

"A Toeplitz matrix has the same elements on every diagonal from top-left to bottom-right."

Toeplitz Matrix - Array - Easy - LeetCode

A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

Now given an M x N matrix, return True if and only if the matrix is Toeplitz.

Example 1:

Input: matrix = [ [1,2,3,4], [5,1,2,3], [9,5,1,2] ] Output: True Explanation: In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True. Example 2:

Input: matrix = [ [1,2], [2,2] ] Output: False Explanation: The diagonal "[1, 2]" has different elements.

Note:

matrix will be a 2D array of integers. matrix will have a number of rows and columns in range [1, 20]. matrix[i][j] will be integers in range [0, 99].

Follow up:

What if the matrix is stored on disk, and the memory is limited such that you can only load at most one row of the matrix into the memory at once? What if the matrix is so large that you can only load up a partial row into the memory at once?

public class Solution {
 public bool IsToeplitzMatrix(int[][] matrix) {
 int row = matrix.Length;
 int column = matrix[0].Length;
 for(int i=0;i<row-1;i++){
 for(int j=0;j<column-1;j++){
 if(matrix[i][j]!=matrix[i+1][j+1]){
 return false;
 }
 }
 }
 
 return true;
 }
}

Time Complexity: O(m*n)

Space Complexity: O(1)

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sumitc91

Published on 26 September 2020 · 1 min read · 217 words

Part of AskGif Blog · coding

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