Min Cost Climbing Stairs - Array - Easy - LeetCode
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Min Cost Climbing Stairs - Array - Easy - LeetCode

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  • 1The problem involves calculating the minimum cost to reach the top of a staircase with given costs for each step.
  • 2You can start from either the first or second step and can climb one or two steps at a time.
  • 3The solution has a time complexity of O(n) and a space complexity of O(1).

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Key Insight
AskGif

"The problem involves calculating the minimum cost to reach the top of a staircase with given costs for each step."

Min Cost Climbing Stairs - Array - Easy - LeetCode

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed).

Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step with index 0, or the step with index 1.

Example 1: Input: cost = [10, 15, 20] Output: 15 Explanation: Cheapest is start on cost[1], pay that cost and go to the top. Example 2: Input: cost = [1, 100, 1, 1, 1, 100, 1, 1, 100, 1] Output: 6 Explanation: Cheapest is start on cost[0], and only step on 1s, skipping cost[3]. Note: cost will have a length in the range [2, 1000]. Every cost[i] will be an integer in the range [0, 999]

public class Solution {
 public int MinCostClimbingStairs(int[] cost) {
 if(cost.Length==0){
 return 0;
 }
 
 if(cost.Length==1){
 return cost[0];
 }
 
 for(int i=2;i<cost.Length;i++){
 cost[i]=Math.Min(cost[i-2],cost[i-1])+cost[i];
 }
 
 return Math.Min(cost[cost.Length-1],cost[cost.Length-2]);
 }
}

Time Complexity: O(n)

Space Complexity: O(1)

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sumitc91

Published on 26 September 2020 · 1 min read · 164 words

Part of AskGif Blog · coding

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