Can Make Arithmetic Progression From Sequence - Array - Easy - LeetCode
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Can Make Arithmetic Progression From Sequence - Array - Easy - LeetCode

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  • 1An array can form an arithmetic progression if the difference between consecutive elements is consistent after rearrangement.
  • 2The solution involves sorting the array and checking the differences between consecutive elements.
  • 3The algorithm has a time complexity of O(nlogn) and a space complexity of O(1).

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"An array can form an arithmetic progression if the difference between consecutive elements is consistent after rearrangement."

Can Make Arithmetic Progression From Sequence - Array - Easy - LeetCode

Given an array of numbers arr. A sequence of numbers is called an arithmetic progression if the difference between any two consecutive elements is the same.

Return true if the array can be rearranged to form an arithmetic progression, otherwise, return false.

Example 1:

Input: arr = [3,5,1] Output: true Explanation: We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive element. Example 2:

Input: arr = [1,2,4] Output: false Explanation: There is no way to reorder the elements to obtain an arithmetic progression.

Constraints:

2 <= arr.length <= 1000 -10^6 <= arr[i] <= 10^6

public class Solution {
 public bool CanMakeArithmeticProgression(int[] arr) {
 Array.Sort(arr);
 if(arr.Length == 1){
 return true;
 }
 int diff = arr[1]-arr[0];
 for(int i=2;i<arr.Length;i++){
 if(arr[i]-arr[i-1] != diff){
 return false;
 }
 }
 return true;
 }
}

Time Complexity: O(nlogn)

Space Complexity: O(1)

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sumitc91

Published on 26 September 2020 · 1 min read · 142 words

Part of AskGif Blog · coding

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Can Make Arithmetic Progression From Sequence - Array - Easy - LeetCode | AskGif Blog