Array Partition I - Array - Easy - LeetCode
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Array Partition I - Array - Easy - LeetCode

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  • 1The task is to maximize the sum of the minimums of n pairs from an array of 2n integers.
  • 2Sorting the array allows for efficient pairing, leading to the optimal solution.
  • 3The provided solution has a time complexity of O(nlogn) and a space complexity of O(1).

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"The task is to maximize the sum of the minimums of n pairs from an array of 2n integers."

Array Partition I - Array - Easy - LeetCode

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1: Input: [1,4,3,2]

Output: 4 Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4). Note: n is a positive integer, which is in the range of [1, 10000]. All the integers in the array will be in the range of [-10000, 10000].

public class Solution {
 public int ArrayPairSum(int[] nums) {
 Array.Sort(nums);
 int sum = 0;
 for(int i=0;i<nums.Length;i+=2){
 sum+=nums[i];
 }
 return sum;
 }
}

Time Complexity: O(nlogn)

Space Complexity: O(1)

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sumitc91

Published on 26 September 2020 · 1 min read · 123 words

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Array Partition I - Array - Easy - LeetCode | AskGif Blog