Contains Duplicate - Array - Easy - LeetCode
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Contains Duplicate - Array - Easy - LeetCode

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  • 1The function checks for duplicates in an array of integers and returns true if any value appears at least twice.
  • 2Example inputs demonstrate the function's behavior with both duplicate and distinct elements.
  • 3The algorithm has a time complexity of O(n) and a space complexity of O(n).

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"The function checks for duplicates in an array of integers and returns true if any value appears at least twice."

Contains Duplicate - Array - Easy - LeetCode

Given an array of integers, find if the array contains any duplicates.

Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

Example 1:

Input: [1,2,3,1] Output: true Example 2:

Input: [1,2,3,4] Output: false Example 3:

Input: [1,1,1,3,3,4,3,2,4,2] Output: true

public class Solution {
 public bool ContainsDuplicate(int[] nums) {
 var set = new HashSet<int>();
 for(int i=0;i<nums.Length;i++){
 if(set.Contains(nums[i])){
 return true;
 }
 set.Add(nums[i]);
 }
 
 return false;
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

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sumitc91

Published on 25 September 2020 · 1 min read · 87 words

Part of AskGif Blog · coding

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