Best Time to Buy and Sell Stock II - Array - Easy - LeetCode
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Best Time to Buy and Sell Stock II - Array - Easy - LeetCode

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  • 1The algorithm calculates maximum profit by summing positive differences between consecutive stock prices.
  • 2You can perform unlimited transactions but must sell before buying again.
  • 3If stock prices are in descending order, no profit can be made, resulting in a maximum profit of zero.

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"The algorithm calculates maximum profit by summing positive differences between consecutive stock prices."

Best Time to Buy and Sell Stock II - Array - Easy - LeetCode

Say you have an array prices for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).

Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).

Example 1:

Input: [7,1,5,3,6,4] Output: 7 Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4. Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3. Example 2:

Input: [1,2,3,4,5] Output: 4 Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4. Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are engaging multiple transactions at the same time. You must sell it before buying it again. Example 3:

Input: [7,6,4,3,1] Output: 0 Explanation: In this case, no transaction is done, i.e. max profit = 0.

Constraints:

1 <= prices.length <= 3 * 10 ^ 4 0 <= prices[i] <= 10 ^ 4

public class Solution {
 public int MaxProfit(int[] prices) {
 int profit = 0;
 for(int i=1;i<prices.Length;i++){
 profit += Math.Max(0,prices[i]-prices[i-1]);
 }
 
 return profit;
 }
}

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sumitc91

Published on 25 September 2020 · 1 min read · 240 words

Part of AskGif Blog · coding

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Best Time to Buy and Sell Stock II - Array - Easy - LeetCode | AskGif Blog