Given two integer arrays arr1 and arr2, and the integer d, return the distance value between the two arrays.
The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where |arr1[i]-arr2[j]| <= d.
Example 1:
Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
Output: 2
Explanation:
For arr1[0]=4 we have:
|4-10|=6 > d=2
|4-9|=5 > d=2
|4-1|=3 > d=2
|4-8|=4 > d=2
For arr1[1]=5 we have:
|5-10|=5 > d=2
|5-9|=4 > d=2
|5-1|=4 > d=2
|5-8|=3 > d=2
For arr1[2]=8 we have:
|8-10|=2 <= d=2
|8-9|=1 <= d=2
|8-1|=7 > d=2
|8-8|=0 <= d=2
Example 2:
Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
Output: 2
Example 3:
Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
Output: 1
Constraints:
1 <= arr1.length, arr2.length <= 500
-10^3 <= arr1[i], arr2[j] <= 10^3
0 <= d <= 100
Solution:
using System;
using System.Collections.Generic;
using System.Text;
namespace LeetCode.AskGif.Easy.Array
{
public class FindTheDistanceValueSoln
{
public int FindTheDistanceValue(int[] arr1, int[] arr2, int d)
{
int count = 0;
for (int i = 0; i < arr1.Length; i++)
{
bool found = false;
for (int j = 0; j < arr2.Length; j++)
{
if (Math.Abs(arr1[i] - arr2[j]) <= d)
{
found = true;
break;
}
}
if (!found)
{
count++;
}
}
return count;
}
}
}
Time Complexity: O(m*n) Where m and n are the length of the array.
Space Complexity: O(1)
Unit Tests:
using LeetCode.AskGif.Easy.Array;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System;
using System.Collections.Generic;
using System.Text;
namespace CodingUnitTest.Easy.Array
{
[TestClass]
public class FindTheDistanceValueSolnTests
{
[TestMethod]
public void FindTheDistanceValueSoln_First()
{
var arr1 = new int[] { 4, 5, 8 };
var arr2 = new int[] { 10, 9, 1, 8 };
var d = 2;
var output = 2;
var res = new FindTheDistanceValueSoln().FindTheDistanceValue(arr1, arr2, d);
Assert.AreEqual(res, output);
}
[TestMethod]
public void FindTheDistanceValueSoln_Second()
{
var arr1 = new int[] { 1, 4, 2, 3 };
var arr2 = new int[] { -4, -3, 6, 10, 20, 30 };
var d = 3;
var output = 2;
var res = new FindTheDistanceValueSoln().FindTheDistanceValue(arr1, arr2, d);
Assert.AreEqual(res, output);
}
[TestMethod]
public void FindTheDistanceValueSoln_Third()
{
var arr1 = new int[] { 2, 1, 100, 3 };
var arr2 = new int[] { -5, -2, 10, -3, 7 };
var d = 6;
var output = 1;
var res = new FindTheDistanceValueSoln().FindTheDistanceValue(arr1, arr2, d);
Assert.AreEqual(res, output);
}
}
}



