Make Two Arrays Equal by Reversing Sub-arrays - Easy - LeetCode
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Make Two Arrays Equal by Reversing Sub-arrays - Easy - LeetCode

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  • 1You can convert the array 'arr' to 'target' by reversing sub-arrays any number of times.
  • 2The solution involves checking if both arrays contain the same elements with the same frequencies.
  • 3If any element in 'target' is missing from 'arr', it is impossible to make them equal.

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"You can convert the array 'arr' to 'target' by reversing sub-arrays any number of times."

Make Two Arrays Equal by Reversing Sub-arrays - Easy - LeetCode

Given two integer arrays of equal length target and arr.

In one step, you can select any non-empty sub-array of arr and reverse it. You are allowed to make any number of steps.

Return True if you can make arr equal to target, or False otherwise.

Example 1:

Input: target = [1,2,3,4], arr = [2,4,1,3]

Output: true

Explanation: You can follow the next steps to convert arr to target:

1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3]

2- Reverse sub-array [4,2], arr becomes [1,2,4,3]

3- Reverse sub-array [4,3], arr becomes [1,2,3,4]

There are multiple ways to convert arr to target, this is not the only way to do so.

Example 2:

Input: target = [7], arr = [7]

Output: true

Explanation: arr is equal to target without any reverses.

Example 3:

Input: target = [1,12], arr = [12,1]

Output: true

Example 4:

Input: target = [3,7,9], arr = [3,7,11]

Output: false

Explanation: arr doesn't have value 9 and it can never be converted to target.

Example 5:

Input: target = [1,1,1,1,1], arr = [1,1,1,1,1]

Output: true

Constraints:

target.length == arr.length

1 <= target.length <= 1000

1 <= target[i] <= 1000

1 <= arr[i] <= 1000

Solution:

using System;
using System.Collections.Generic;
using System.Text;

namespace LeetCode.AskGif.Easy.Array
{
 public class CanBeEqualSoln
 {
 public bool CanBeEqual(int[] target, int[] arr)
 {
 var map = new Dictionary<int, int>();
 for (int i = 0; i < arr.Length; i++)
 {
 if (map.ContainsKey(arr[i]))
 {
 map[arr[i]]++;
 }
 else
 {
 map.Add(arr[i], 1);
 }
 }

 for (int i = 0; i < target.Length; i++)
 {
 if (!map.ContainsKey(target[i]))
 {
 return false;
 }

 if (map[target[i]] == 1)
 {
 map.Remove(target[i]);
 }
 else
 {
 map[target[i]]--;
 }
 }

 return true;
 }
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

Unit Tests:

using LeetCode.AskGif.Easy.Array;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System;
using System.Collections.Generic;
using System.Text;

namespace CodingUnitTest.Easy.Array
{
 [TestClass]
 public class CanBeEqualSolnTests
 {
 [TestMethod]
 public void CanBeEqualSoln_First()
 {
 var target = new int[] { 1, 2, 3, 4 };
 var arr = new int[] { 2, 4, 1, 3 };
 var output = true;
 var res = new CanBeEqualSoln().CanBeEqual(target, arr);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void CanBeEqualSoln_Second()
 {
 var target = new int[] { 3, 7, 9 };
 var arr = new int[] { 3, 7, 11 };
 var output = false;
 var res = new CanBeEqualSoln().CanBeEqual(target, arr);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void CanBeEqualSoln_Third()
 {
 var target = new int[] { 7 };
 var arr = new int[] { 7 };
 var output = true;
 var res = new CanBeEqualSoln().CanBeEqual(target, arr);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void CanBeEqualSoln_Fourth()
 {
 var target = new int[] { 1, 12 };
 var arr = new int[] { 12, 1 };
 var output = true;
 var res = new CanBeEqualSoln().CanBeEqual(target, arr);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void CanBeEqualSoln_Fifth()
 {
 var target = new int[] { 1, 1, 1, 1, 1 };
 var arr = new int[] { 1, 1, 1, 1, 1 };
 var output = true;
 var res = new CanBeEqualSoln().CanBeEqual(target, arr);

 Assert.AreEqual(res, output);
 }
 }
}

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AskGif

Published on 5 June 2020 · 2 min read · 493 words

Part of AskGif Blog · coding

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