Roman to Integer - String - Easy - LeetCode
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Roman to Integer - String - Easy - LeetCode

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  • 1Roman numerals consist of seven symbols: I, V, X, L, C, D, and M, each representing specific values.
  • 2Subtraction is used in specific cases, such as IV for 4 and IX for 9, to denote smaller values before larger ones.
  • 3The algorithm to convert Roman numerals to integers has a time complexity of O(n) and a space complexity of O(n).

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"Roman numerals consist of seven symbols: I, V, X, L, C, D, and M, each representing specific values."

Roman to Integer - String - Easy - LeetCode

Roman numerals are represented by seven different symbols: I, V, X, L, C, D, and M.

Symbol Value

I 1

V 5

X 10

L 50

C 100

D 500

M 1000

For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which is simply X + II. The number twenty seven is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

I can be placed before V (5) and X (10) to make 4 and 9.

X can be placed before L (50) and C (100) to make 40 and 90.

C can be placed before D (500) and M (1000) to make 400 and 900.

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.

Example 1:

Input: "III"

Output: 3

Example 2:

Input: "IV"

Output: 4

Example 3:

Input: "IX"

Output: 9

Example 4:

Input: "LVIII"

Output: 58

Explanation: L = 50, V= 5, III = 3.

Example 5:

Input: "MCMXCIV"

Output: 1994

Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

Solution:

using System;
using System.Collections.Generic;
using System.Text;

namespace LeetCode.AskGif.Easy.String
{
 public class RomanToIntSoln
 {
 public int RomanToInt(string s)
 {
 var map = new Dictionary<char, int>();
 map.Add('I',1);
 map.Add('V', 5);
 map.Add('X', 10);
 map.Add('L', 50);
 map.Add('C', 100);
 map.Add('D', 500);
 map.Add('M', 1000);

 int sum = 0;
 for (int i = s.Length - 1; i >= 0; i--)
 {
 if(i == s.Length - 1)
 {
 sum += map[s[i]];
 }
 else
 {
 if (map[s[i]] < map[s[i + 1]])
 {
 sum -= map[s[i]];
 }
 else
 {
 sum += map[s[i]];
 }
 }
 }

 return sum;
 }
 }
}

Time Complexity: O(n)

Space Complexity: O(n)

Unit Tests:

using LeetCode.AskGif.Easy.String;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System;
using System.Collections.Generic;
using System.Text;

namespace CodingUnitTest.Easy.String
{
 [TestClass]
 public class RomanToIntSolnTests
 {
 [TestMethod]
 public void RomanToIntSoln_First()
 {
 var input = "III";
 var output = 3;
 var res = new RomanToIntSoln().RomanToInt(input);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void RomanToIntSoln_Second()
 {
 var input = "IV";
 var output = 4;
 var res = new RomanToIntSoln().RomanToInt(input);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void RomanToIntSoln_Third()
 {
 var input = "IX";
 var output = 9;
 var res = new RomanToIntSoln().RomanToInt(input);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void RomanToIntSoln_Fourth()
 {
 var input = "LVIII";
 var output = 58;
 var res = new RomanToIntSoln().RomanToInt(input);

 Assert.AreEqual(res, output);
 }

 [TestMethod]
 public void RomanToIntSoln_Fifth()
 {
 var input = "MCMXCIV";
 var output = 1994;
 var res = new RomanToIntSoln().RomanToInt(input);

 Assert.AreEqual(res, output);
 }
 }
}

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Published on 5 June 2020 · 2 min read · 476 words

Part of AskGif Blog · coding

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