Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
Solution:
using System;
using System.Collections.Generic;
using System.Text;
namespace LeetCode.Easy
{
class TwoSumSolution
{
public int[] TwoSum(int[] nums, int target)
{
var res = new int[2];
for (int i = 0; i < nums.Length; i++)
{
for (int j = i+1; j < nums.Length; j++)
{
if(nums[i]+nums[j]==target)
{
res[0] = i;
res[1] = j;
return res;
}
}
}
return res;
}
}
}
Time Complexity: O(n^2)
Space Complexity: O(1)
Detail: https://github.com/sumitc91/coding/blob/master/Coding/LeetCode/Easy/TwoSumSolution.cs



